WebbThe product of two numbers is 2028 and their HCF is 13. The number of such pairs is A 1 B 2 C 3 D 4 Medium Solution Verified by Toppr Correct option is B 2 Let the two numbers be x and y respectively. It is given that the product of the two numbers is 2028, therefore, xy=2028 Also 13 is their HCF, thus both numbers must be divisible by 13. WebbThe product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: Answer: B) 2 Explanation: Let the numbers 13a and 13b. Then, 13a x 13b = 2028 =>ab = …
The product of two numbers is 2028 and their H C - Examveda
WebbWe are supposed to find the l cm of the 2 numbers. We have a formula that says that the product of 2 numbers is equal to the product of 2 ... The product of two numbers is … WebbCorrect Answer; 2 Explanation Let the numbers 13 a and 13 b Then, 13a x 13b = 2028 . ab = 12.. Now, the co-primes with product 12 are (1, 12) and (3, 4). [Note: Two integers a and … tti group warranty portal
if the HCF of two number is 13, and LCM is 182. find the product of two …
WebbThe product of two numbers is 2028 and their HCF is 13. The number of such pairs is : A] 1 B] 2 C] 3 D] 4 Quantitative Aptitude Quiz fresherbell.com Webb26 juli 2024 · The product of two numbers HCF of two numbers = 13 . LCM of two numbers = 182. Now here's a relation between HCF , LCM amd product of two numbers. ⇒ HCF × LCM = Product of two numbers. ⇒Product of two numbers = 13 × 182. Hence the product of two numbers is 2366. Find Math textbook solutions? Class 4 Class 3 Class 2 Class 1 … WebbThe product of two numbers is 5476. If the HCF of these numbers is 37. The greater number is: A] 107 B] 111 C] 148 D] 185. The product of two numbers is 2028 and their HCF is 13. How many pairs of such numbers are possible? A] 1 B] 2 C] 3 D] 4. tti-group.workexpert.online